It states zero or more prevalence of whitespace characters, accompanied by a comma and afterwards followed by zero or even more occurrence of whitespace figures. However x.replaceAll("\s+", ""); will likely be a lot more economical strategy for trimming spaces (if string might have many contiguous spaces) for the reason that https://mantra-chocolate-bars99753.sharebyblog.com/31223881/not-known-details-about-mantra-mushroom-chocolate-bars